## MS Mod 4 t values and two confidence intervals practice exam questions...

 Author Message NEAS Supreme Being         Group: Administrators Posts: 4.2K, Visits: 1.2K MS Module 4 t values and two confidence intervals practice exam questionsA statistician estimates the population mean for a normal distribution from a sample of 6 points. ●    The upper bound of the 99% confidence interval for the population mean is 5.78.●    The lower bound of the 95% confidence interval for the population mean is 1.4.Question 4.1: Critical t valueWhat is the critical t value for a 99% confidence interval from a sample of 6 points?Answer 4.1: 4.0321 (table look-up)Question 4.2: Critical t valueWhat is the critical t value for a 95% confidence interval from a sample of 6 points?Answer 4.2: 2.5706 (table look-up)Question 4.3: Standard error of estimated meanWhat is the standard error of the estimated mean of the population?Answer 4.3: (5.78 – 1.4) / (4.0321 + 2.5706) = 0.6634(standard error of the estimated mean of the population = (upper bound of first confidence interval – lower bound of second confidence interval) / (critical t value of first confidence interval + critical t value of second confidence interval)Question 4.4: Standard deviation of the sampleWhat is the standard deviation of the sample?Answer 4.4: 0.6634 × 60.5 = 1.625(standard deviation of the sample = standard error of the estimated mean of the population × square root of the number of observations in the sample)Question 4.5: Estimated mean of the populationWhat is the estimated mean of the population? Answer 4.5: (two formulas:)●    5.78 – 4.0321 × 0.6634 = 3.105●    1.4 + 2.5706 × 0.6634 = 3.105(estimated mean of the population = upper bound of the confidence interval – critical t value × standard error of the estimated mean OR lower bound of the confidence interval + critical t value × standard error of the estimated mean) Attachments MS Module 4 t valuestwo confidence intervals practice exam questions.pdf (244 views, 31.00 KB)
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