## MS Mod 13: Two-factor ANOVA, one observation per cell – practice...

 Author Message NEAS Supreme Being         Group: Administrators Posts: 4.2K, Visits: 1.2K MS Module 13: Two-factor ANOVA, one observation per cell – practice problems(The attached PDF file has better formatting.) Exercise 13.1: Two-factor ANOVA (one observation per cell)A classification table has two rows, two columns, and one observation in each cell:    Column 1    Column 2Row 1    80    50Row 2    40    20We test whether Row 1 differs from Row 2 and whether Column 1 differs from Column 2. The ANOVA table calls the rows the A dimension and the columns the B dimension, following the usage in the textbook. A.    What is the square of the sum of all the observations, or x..2 ?B.    What is the sum of the squares of all the observations, or i j xij2 ?C.    What is the sum of the squares of the row totals, or j xi..2D.    What is the sum of the squares of the column totals, or j x.j.2E.    What is SST, the total sum of squared deviations?F.    What is SSA, the sum of squared deviations for the i dimension?G.    What is SSB, the sum of squared deviations for the j dimension?H.    What is SSE, the error sum of squared deviations?I.    What are the degrees of freedom for the rows (SSA)?J.    What are the degrees of freedom for the columns (SSB)?K.    What are the degrees of freedom for the total sum of squares (SST)?L.    What are the degrees of freedom for the error sum of squares (SSE)?M.    What is MSA, the mean squared deviation for the rows?N.    What is MSB, the mean squared deviation for the columns?O.    What is MSE, the mean squared error?P.    What is fA, the f value for testing significance of the row differences?Q.    What is fB, the f value for testing significance of the column differences?Part A: The sum of all the observations is     80 + 50 + 40 + 20 = 190The square of this sum is 1902 = 36,100This squared sum, which does not differentiate by row or column, is used for the total sum of squares SST.Part B: The sum of the squares of all the observations is    802 + 502 + 402 + 202 = 10,900Part C: The row totals are 80 + 50 = 130 for Row 1 and 40 + 20 = 60 for Row 2. The sum of squares is    1302 + 602 = 20,500This sum of squares differentiates by row but not by column, so it is used for SSA.    Column 1    Column 2    Total    SquaredRow 1    80    50    130    16,900Row 2    40    20    60    3,600Total    120    70    190    20,500Squared    14,400    4,900    19,300    Part D: The column totals are 80 + 40 = 120 for Column 1 and 50 + 20 = 70 for Column 2. The sum of squares is    1202 + 702 = 19,300This sum of squares differentiates by column but not by row, so it is used for SSB.Part E: SST = i j xij2 – x..2 / N = 10,900 – 36,100 / 4 = 1,875.00Part F: SSA =     the sum of squares of the row totals ÷ the number of columns–     the square of the sum of all the observations ÷ the number of observations =    ½ × 20,500 – 36,100 / 4 = 1,225.00Part G: SSB =     the sum of squares of the columns totals ÷ the number of rows–     the square of the sum of all the observations ÷ the number of observations =    ½ × 19,300 – 36,100 / 4 = 625.00Part H: SSE, the error sum of squares, = SST – (SSA + SSB) = 1,875 – (1,225 + 625) = 25Part I: The degrees of freedom for the rows = (the number of rows – 1) = 2 – 1 = 1.Part J: The degrees of freedom for the columns = (the number of columns) – 1 = 2 – 1 = 1.Part K: The degrees of freedom for the total sum of squares = (the number of observations – 1) = 4 – 1 = 3.Part L: The degrees of freedom for the total sum of squares = the sum of the degrees of freedom for SSA, SSB, and SSE ➾ the degrees of freedom for SSE = 3 – 1 – 1 = 1.Part M: MSA, the mean squared deviation for the rows, is SSA / degrees of freedom = 1,225 / 1 = 1,225.Part N: MSB, the mean squared deviation for the columns, is SSB / degrees of freedom = 625 / 1 = 625.Part O: MSE, the mean squared error, is SSE / degrees of freedom = 25 / 1 = 25.Part P: The fA (f value for testing significance of the row differences) is MSA / MSE = 1,225 / 25 = 49.00The p value is F49,1,1 = 0.090334.Part Q: The fB (f value for testing significance of the column differences) is MSB / MSE = 625 / 25 = 25.00The p value is F25,1,1 = 0.125666. Attachments MS Module 13 Two-factor ANOVA, one observation – practice problems df.pdf (371 views, 50.00 KB)
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